The red cells of a nonsecretor (se/se) will most likely type as which of the following?

A nonsecretor, identified genetically by the genotype se/se, lacks the ability to produce soluble H antigens in bodily secretions, which impacts the expression of certain antigens on red blood cells. One of these antigens is the Lewis antigen.

In individuals with the Le gene, the phenotype of their red blood cells can be categorized as Le(a+b-), Le(a-b+), Le(a+b+), or Le(a-b-). Nonsecretors usually express only the Le(a) antigen in a low prevalence, resulting in a situation where only the antigen that corresponds to their phenotype from the underlying genetics is produced.

For nonsecretors, the expected phenotype is Le(a+b-). This is because the presence of sialic acid on the red blood cells is affected by their secretor status, which means they cannot truly express the Lewis b antigen in the same manner as secretors. Therefore, individuals with the genotype se/se will most likely type as Le(a+b-), showing that they express Lewis a but not Lewis b antigens on their red cells, which fits with the mechanisms of antigen formation in relation to secretor status.